Question

The increase in kinetic energy of a body of mass 500g,when it's speed increases from 2ms-¹ to 4ms-¹ is​

Answer 1

Answer:

The increase in kinetic energy of the body will be 3 J.

Explanation:

The kinetic energy of an object having mass m and velocity v is given by the equation:

                        K.E = (mv²) / 2

Here the mass of the body is given as 500 g, which is equivalent to 0.5 Kg.

The kinetic energy of the body when its speed is 2 m/s is:

K.E = (mv²) / 2

     = (0.5 × 2²) / 2

     = 2/2

K.E = 1 J

The kinetic energy of the body when its speed is 4 m/s is:

K.E = (mv²) / 2

     = (0.5 × 4²) / 2

K.E = 4 J

So the increase in kinetic energy of the body when its speed increased from 2 m/s to 4 m/s is​:

4 - 1 = 3 J