Question

The increase in temperature of aluminium rod is 100x°. If its length is to be increasd by 1%. Then
the x value - [- for aluminium = 25 x 10-7°C]​

Answer 1

Answer:

∆L = L alpha ∆T

∆L/L = alpha ∆T

∆L/L = 10^-1

∆T = 10^-1/25 × 10^-7

∆T = 4 × 10^4

4 × 10^4 = 100x

x = 400

Thanks for Reading