Question

The increase in the length of a bar of length l area A, modulus of elasticity E due to a tensile load P is given

Answer 1

Answer:

Use the formula,

\bold{\text{Young's modulus }} =\bold{\frac{stress}{strain}}Young’s modulus =

strain

stress

stress = Force/Area = F/A

strain = change in length/original length = ∆L/L

so, Young's modulus of elasticity = FL/A∆L

Here, Force ( tension ) = P, Area = A , Length = L

And Young's modulus = E ,

E = PL/A∆L

∆L = PL/AE

Hence, change in length or increase in length = PL/AE