Question

The increase in velocity acquired by a 10 kg mass in 5 seconds due to a force of 10 newton is​

Answer 1

Answer :

• Increase in velocity = 5 m/s

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Given :

• Mass = 10 kg

• Time = 5 seconds

• Force = 10 N

To Find :

• Increase in velocity

Solution :

• We know that , F = ma

Substitute the values here ,

$\implies \sf a \:=\: \dfrac{10}{10}$

$\implies \sf Acceleration \:=\: 1\:m/s$

• Now , since we have found value of acceleration , we can apply first equation of motion here , i.e. v = u + at .

• Now , let us consider initial velocity (u) to be 0 .

$\implies \sf v \:=\: 0\:+\:(1)(5)$

$\implies \sf v \:=\: 5\:m/s$

• Increase in velocity = 5 m/s

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Answer 2

Given:

10 N force acts on a 10 kg mass for 5 seconds.

To find:

Increase in velocity ?

Calculation:

First of all, let's define force :

• Force is defined as the rate of change of momentum with respect to time.

$F = \dfrac{\Delta P}{\Delta t}$

• ∆P is change in momentum and ∆t refers to time. Now ∆P can be written as (m × ∆v) , ∆v means change in velocity.

$\implies F = \dfrac{m\Delta v}{\Delta t}$

• Putting necessary values in SI units:

$\implies 10 = \dfrac{10 \times \Delta v}{5}$

$\implies \Delta v = 5 \: m {s}^{ - 1}$

So, increase in velocity (i.e. ∆v) is 5 m/s