Question

The increase in velocity of a freely falling body in 1 sec is
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Answer 1

By definition, it is equal to the acceleration times time, i.e. 9.8 m/s

Answer 2

Answer:

hope it helps....

Explanation:

I’m guessing that your body is on Earth.

The equation of motion you can use here is Vf = Vi + at where Vf is final velocity, Vi is initial velocity, a is acceleration, and t is time.

Let’s plug in the numbers. Vi can be 0 m/s because the object is dropped, a can 9.8 m/s^2 because that is the acceleration due to gravity, t is one second.

Vf = 0m/s + 9.8m/s*1s

Vf = 9.8 m/s.

However, for a problem this simple, it’s better to look at what acceleration actually means. When the acceleration is 9.8 m/s^2, it means that the velocity of the object increases by 9.8 m/s every second. So if the object has a velocity of 0 m/s now, it will have a velocity of 9.8 m/s in 1 second.