Math, asked by kartikays1486, 1 year ago

The increase of population of town is 10%every year. If the present population is 100000 what will be the population in after 3 years

Answers

Answered by Anonymous
11

Given :

  • The increase of population of town is 10% every year.
  • The present population is 100000.

To find :

  • What will be the population in after 3 years ?

Solution :

Formula Used :-

{\boxed{\bold{Uniform\:rate\: of\: growth=p(1+\dfrac{r}{100})^n}}}

  • Terms identification :
  • p = Population
  • r = Rate of increasing population.
  • n = time (years)

Here,

  • p = 100000
  • r = 10%
  • n = 3 years

After 3 years, the population will be ,

\implies\sf{100000(1+\dfrac{10}{100})^3}

\implies\sf{100000(1+\dfrac{1}{10})^3}

\implies\sf{100000\times(\dfrac{11}{10})^3}

\implies\sf{100000\times\dfrac{11}{10}\times\dfrac{11}{10}\times\dfrac{11}{10}}

\implies\sf{100\times\:11\times\:11\times\:11}

\implies\sf{133100}

Therefore,

After 3 years, the population will be 133100 .

______________________

Answered by silentlover45
1

  \huge \mathfrak{Answer:-}

\implies 133100

\large\underline\mathrm{Given:-}

  • The increase of population of town is 10%every year.
  • The present population is 100000.

\large\underline\mathrm{To \: find}

  • what will be the population in after 3 years.

\large\underline\mathrm{Using \: formula}

  • p = 100000
  • r = 10%
  • n = 3 years

\large\underline\mathrm{Solution}

\implies 100000(1 + 10/100)3

\implies 100000(1 + 1/10)3

\implies 100000 × 11/10³

\implies 100000 × 11/10 × 11/10 × 11/10

\implies 100 × 11 × 11 × 11

\implies 133100

\large\underline\mathrm{hence,}

\large\underline\mathrm{After \: 3 \: year's, \: the \: population \: will \: be \: 133100.}

\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}

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