Question

The increasing order of effusion among the gases,
H2, 02, NH3 and CO2 is -
(a) H2, CO2, NH3, 02 (b) Hz, NH3, 02, CO2
(c) H2, 02. NH3.CO2 (d) CO2.02. NH3, H2​

Answer 1

option (d) is correct

CO2, O2, NH3, H2

Apply r= √1/M. Graham's law.

the gas with lower molecular mass effuses faster.

CO2(44) < O2(32) < NH3(17) < H2(2)

i hope it help you.

Answer 2

The increasing order of effusion among the gases is $CO_2$ <  $O_2$ < $NH_3$ < $H_2$

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

Molar mass of the hydrogen $H_2$ gas = 2 g/mol

Molar mass of the carbon dioxide $CO_2$ gas = 44 g/mol

Molar mass of the ammonia $NH_3$ gas = 17 g/mol

Molar mass of the oxygen $O_2$ gas = 32g/mol

As the decreasing order of molar mass is :  $CO_2$ <  $O_2$ < $NH_3$ < $H_2$, the increasing order of effusion is  :  $CO_2$ <  $O_2$ < $NH_3$ < $H_2$.

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