Question

the increasing order of ionic radii of Na+,Mg+2,Li+3

Answer 1

Answer:

The more + the charge, the smaller the ionic radius. Remember that - means adding electrons. These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be:

Li+3<Mg2+<Na+

Answer 2

To find:

the increasing order of ionic radii of Na+,Mg+2,Al+3

Solution:

In the ions provided above , all of them are in noble gas configuration with same number of electrons.

• But , the number of protons is highest in Aluminium (+3 ion), then Magnesium(+2 ion) and then Sodium(+1 ion).

• So , the electrons will be maximum attracted by the nucleus in Al+3 , then Mg+2 and then Na+.

• This attraction will govern the ionic radii.

So, increasing order:

$\boxed{ \bf{ \large{{Al}^{ + 3} < {Mg}^{ + 2} < {Na}^{ + 1} }}}$