Question

The increasing order of reducing power of the halogen acids is
(a) HF < HCl < HBr < HI
(b) HI < HBr < HCl < HF
(c) HBr < HCl < HF < HI
(d) HCl < HBr < HF < HI

Answer 1

Answer:

☑️☑️(d) HCl<HBr<HF<HI☑️☑️

Answer 2

The increasing order of reducing the power of the halogen acids is HF < HCl < HBr < HI.

• As we move from HI to HF the size of the halogen decreases and the reducing property also decreases.
• The size of I is very large and has a weak H-I bond which can be easily broken down and it has the highest reducing power.
• Thus the increasing order of reducing the power of the halogen acids is HF < HCl < HBr < HI.
• The correct option is a.

#SPJ3