the Indian hockey federation organised a friendly hockey match between India and Pakistan on a circular ground this khel processed of this maths all be donated to an orphanage a rectangular proof is spread on the ground as shown in figure find the radius of the stadium be using social value in the peated hair see how does donation to corrector able organisation help in the development of society
Answers
Answer:
Directions (1-3): Select the phrase/connector (STARTERS) from the given three options which can be used to form a single sentence from the two sentences given below, implying the same meaning as expressed in the statement sentences.
Given :-
Length of Rectangular turf = 80 m.
Breadth = 60 m .
To Find :-
1. the radius of the staduim is?
2. find the area of rectangular field
3. fine the perimeter of circular ground ( take circumference as 22/7)
4. find the area of circular ground.
5. find the area of shaded portion
Solution :-
from image we can see that,
→ ABCD = Rectangle .
→ AB = DC = 60 m .
→ CB = 80 m.
→ ∠DCB = 90° . (Each angle of a rectangle is equal to 90°.)
then, in Right ∆DCB, we have,
→ DC² + CB² = BD²
→ 60² + 80² = BD²
→ BD² = 3600 + 6400
→ BD² = 10000
→ BD = √(10000)
→ BD = 100 m
so,
→ Radius of the stadium = BD/2 = 100/2 = 50 m (Ans.1)
and,
→ Area of rectangular field = Length * Breadth = 60 * 80 = 4800 m². (Ans.2)
also,
→ The perimeter of circular ground = 2πr = 2 * (22/7) * 50 = (2200/7) = 314.28 m . (Ans.3)
and,
→ The area of circular ground = π(r)² = (22/7) * 50 * 50 = (55000/7) = 7857.14m² (Ans.4)
therefore,
→ The area of shaded region = The area of circular ground - Area of rectangular field = 7857.14 - 4800 = 3057.14m² (Ans.5)
