Physics, asked by PrasannaPawar, 2 months ago

The individual sensitivities of
different elements comprising
a temperature measuring system
transducer = 0.3 ohm/C
Wheatstone bridge = 0.01 V/ohm
Amplifier gain = 80 v/v
pen recorder - 1.2 mm/V
Determine the overall
overall sensitivity in mm/C.​

Answers

Answered by rushrockb24
7

Answer:

The individual sensitivities of different elements comprising a temperature measuring system are:

Transducer 0.3 Ω/0C

Wheatstone bridge 0.01 V/Ω

Amplifier gain 80 V/V

Pen recorder 0.12 cm/V

Determine the overall sensitivity and the temperature change corresponding to a recorder pen movement of 3 cm.

Answered by harihardik16
0

Answer:0.0288 cm/°C and 104.167 °C

Explanation:

The given data has the individual sensitivities

overall sensitivity

0.3*0.01*80*1.2=0.0288 cm/°C

Therefore the overall sensitivity is 0.0288 cm/°C

we got 0.0288cm movement of recorder pen for 1 °C .so the temperature change for 3cm will be :

Temperature change=3/0.0288=104.167 °C

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