Question

The inductance of a solenoid is 500 and the resistance is 5 ohm if it is connected to a 10 volt battery then time taken by the current to reach nine tenth of its maximum will be

Answer 1

We know,

I= I₀{1-e^(-Rt/L)}----- (1)

where, I₀= maximum current

According to question, I= (9/10)I₀

                                       I/I₀= 9/10

(1)=> I/I₀= 1-e^(-Rt/L)

   =>9/10= 1-e^(-5t/500)

   => e^(-5t/500)= 1/10

        =>-(t/100)= ln(1/10)

        =>-2.30= -(t/100)

         => t= 230 s

Answer 2

Answer:

Explanation:see the pic for your perfect answer