Question

The infinite gp with first term 1/4 and sum 1/3 is

Answer 1

Step-by-step explanation:

a=1/4

S=1/3

$s \infty = \frac{a}{1 - r}$

$\frac{1}{3} = \frac{ \frac{1}{4} }{1 - r}$

$\frac{1 - r}{3} = \frac{1}{4}$

$4 - 4r = 3$

$- 4r = 3 - 4$

$r - \frac{ - 1}{ - 4}$

$r = \frac{1}{4}$

First 3 term of GP are

1/4

1/4*1/4=1/16

1/16*1/4=1/64

1/4, 1/16 , 1/64 ......

Plz mark brainliest