the initial and final temperature of an oil bath are 25 plus minus 0.1 degree celsius and 50 plus minus 0.2 degree celsius respectively what is the rise of temperature
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The temperatures of the two baths are 25±0.1 and 50±0.2, which is 298.15±0.1K and 323.15±0.2 the ratio is the range
323.35/298.05 = 1.0849 or 322.95/298.25 = 1.0828
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Answer:
The rise in the temperature of oil bath is equal to (25 ± 0.1)°C.
Explanation:
We have given,
The initial temperature (T₁) of the oil bath is:
T₁ = (25 ± 0.1)°C
The final temperature (T₂) of the oil bath is:
T₂ = (50 ± 0.2)°C
The rise in the temperature can be calculated by subtracting the final temperature from initial temperature.
ΔT = T₂ - T₁
ΔT = (50 ± 0.2) - (25 ± 0.1)
ΔT = (50 - 25) ± (0.2 - 0.1)
ΔT = (25 ± 0.1)°C
Therefore, the rise in the temperature of the oil bath is equal to (25 ± 0.1)°C.
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