Physics, asked by shivamagg2612, 10 months ago

the initial and final temperature of an oil bath are 25 plus minus 0.1 degree celsius and 50 plus minus 0.2 degree celsius respectively what is the rise of temperature

Answers

Answered by Sukhpreet85
21

The temperatures of the two baths are 25±0.1 and 50±0.2, which is 298.15±0.1K and 323.15±0.2 the ratio is the range

323.35/298.05 = 1.0849 or 322.95/298.25 = 1.0828

Answered by KaurSukhvir
2

Answer:

The rise in the temperature of oil bath is equal to (25 ± 0.1)°C.

Explanation:

We have given,

The initial temperature (T₁) of the oil bath is:

T₁ = (25 ± 0.1)°C

The final temperature (T₂) of the oil bath is:

T₂ = (50 ± 0.2)°C

The rise in the temperature can be calculated by subtracting the final temperature from initial temperature.

ΔT = T₂ - T₁

ΔT = (50 ± 0.2) - (25 ± 0.1)

ΔT = (50 - 25) ± (0.2 - 0.1)

ΔT = (25 ± 0.1)°C

Therefore, the rise in the temperature of the oil bath is equal to  (25 ± 0.1)°C.

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