Question

The initial and final temperatures of a water bath are (18 +-0.5) °C and (40 + -0.3) °C. What is
the rise in temperature of the bath? (2)​

Answer 1

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Answer 2

The change in temperature is $(22\pm 0.8)\ ^{\circ} C$.

Given :

The initial temperature of the water bath is $(18\pm 0.5)^{\circ} C$ and the final temperature of the water bath is $(40\pm 0.3)^{\circ} C$.

To find:

We need to find the rise in temperature of the bath.

Solution :

It means that we need to find the change in temperature. It is given by :

$\Delta T=T_f-T_i\\\\\Delta T=(40\pm 0.3)-(18\pm 0.5)\\\\\Delta T=(40-18)\pm (0.3+0.5)\\\Delta T=(22\pm 0.8)\ ^{\circ} C$

So, the change in temperature is $(22\pm 0.8)\ ^{\circ} C$.

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