Question

the initial and final velocity of a moving body are 30 cm per second and 3.7 metre per second respectively then the distance covered in 5 second will be ​

Answer 1

Answer:

$10 m$

Explanation:

Given:

$v_{i}=30cm/s=0.3m/s$

$v_{f}=3.7m/s$

Δ$t=5s$

Solution:

Δ$d=(\frac{v_{i}+v_{f} }{2 } )t$

Δ$d=(\frac{0.3 m/s+3.7 m/s }{2 } )5s$

Δ$d=10 m$

Answer 2

G I V E N :

• The initial and final velocity of a moving body are 30 cm per second and 3.7 metre per second respectively and time taken is 5 seconds.

T O F I N D :

• Distance covered (s) in 5 seconds = ?

S O L U T I O N :

• Initial Velocity (u) = 30 cm/s = 0.3 m/s
• Final Velocity (v) = 3.7 m/s
• Time Interval (t) = 5 seconds

First of all we have to find acceleration of the body by using first equation of motion :

→ v = u + at

→ 3.7 = 0.3 + a(5)

→ 3.7 - 0.3 = 5a

→ 3.4 = 5a

→ a = 3.4 ÷ 5

→ a = 0.68 m/s²

Therefore, acceleration of the body is 0.68 m/s².

Now, let's calculate the distance covered by the body in 5 seconds by using second equation of motion :

➝ s = ut + ½ at²

➝ s = 0.3 × 5 + ½ × 0.68 × (5)²

➝ s = 1.5 + 0.34 × 25

➝ s = 1.5 + 8.5

➝ s = 10 m

Therefore,distance covered by the body in 5 seconds is 10 m.