Question

The initial lengths of two rods A and B are in the ratio 3:5 and
coefficients of linear expansion are in the ratio 5:3. If the rods are
heated from 34°C to 65°C, the ratio of their expansion will be​

Answer 1

∆L = L@∆T

∆L1 / ∆L2 = (3/5)*(5/3) = 1

Answer 2

Answer:

I am considering it as free expansion case,

so,for free expansion,

the expansion is given by (alpha)*(T)*(l),

where,alpha = coefficient of linear expansion,

T = change in temperature in °c,

l = initial length of the rod,

therefore,

ratio of expansions of two rods will be,

(5*65*3) / (3*65*5) = 1:1.

Hope it helps u...