The initial level of a submarine is 15 m below the sea level. It is descending 6 m per second. What will be its position after 10 seconds?
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Answer:
-75m below sea level
Step-by-step explanation:
initial position=-15m
final pos=initial pos +descending
so, rate of descending is 6m per sec,
time is 10sec
so depriciation is
6*10=-60 m
so now descending ,so -60 m
so final pos is 15+(-60)= -75m
hence,the final pos is -75m below sea level
hope it helps
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