Question

The initial rate of the reaction PCl5 → PCl3 + Cl2is increased a factor of four when the concentration of PCl5 is doubled. Therefore, the rate​

Answer 1

Answer:

Explanation:

Ulsu?

Answer 2

Given info : The initial rate of the reaction PCl5 → PCl3 + Cl2 is increased a factor of four when the concentration of PCl5 is doubled.

Therefore, the rate of reaction ...

solution : for reaction, A => product

rate of reaction, r = k [A]ⁿ

where n indicates order of reaction and [A] is concentration of reactant.

for given reaction,

rate of reaction, r = [PCl5]ⁿ ...(1)

a/c to question, The initial rate of the reaction is increased a factor of four when the concentration of PCl5 is doubled.

so, r₂ = 4r₁ when, [PCl5]₂ = 2[PCl5]₁

from equation (1),

r₁/r₂ = [PCl5]₁ⁿ/[PCl5]₂ⁿ

⇒(1/4) = (1/2)ⁿ

⇒n = 2

Therefore the rate is second order reaction.