Question

The initial speed of a 15-gram bullet
is 600 m/s. It penetrates 10 centimeters
into a stationary target post before it
stops. What is the average force exerted
on the bullet by the target post?​

Answer 1

Answer:

Hong Leong to be able and my order number and I have to do please answer no comments I am I am I have to

Answer 2

Answer:

The following calculation can be used to determine the average force the target post applies to the bullet:

Average force is equal to (mass times velocity change) / time.

Explanation:

Here, we can suppose that the bullet stops in a very brief period of time and that its change in velocity is equal to its initial velocity. Thus, we may express the formula as follows:

Mass times acceleration equals average force.

We are aware that acceleration is determined by dividing the change in velocity by the distance covered. The bullet's path in this instance is 10 centimetres, or 0.1 metres. Hence, we may determine the acceleration as:

Acceleration is calculated as follows:

(0 - 600) / (final velocity - beginning velocity) / distance / 0.1 =

-6000 m/s2

Learn more about Acceleration :

https://brainly.in/question/7645996

#SPJ3