The initial temperature of 150g of ethanol was 22o C. What will be the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol? (Specific heat capacity of ethanol is 2.44 Jo C-1g-1).
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heat=mass(g)×specific heat capacity×temperature change(in celcius or kelvin)
3240=150×2.44×dt
dt=8.85or8.9(approx)
t=8.9+22=30.9°C
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