The initial temperature of 150g of ethanol was 22o C. What will be the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol? (Specific heat capacity of ethanol is 2.44 Jo C-1g-1).
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⭐ Solution ⭐
➡ Q = mst
=> 3240 = 150×2.44×(t2-22°)
=> 3240 = 366(t2-22°)
=> 366(t2-22°) = 3240
=> (t2-22°) = 3240/366
=> t2 - 22° = 540/61
=> t2 - 22° = 540/61 +22
=> t2 = 540+1342/61
=> t2 = 1882/61
=> t2 = 30.80° C
=> t2 = 31°C (approx)
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