the initial temperature of a liquid is recorded as Q1=(25.4+_0.1)°c and on heating its final temperature is recorded asQ2=(52.7+_)°c.find the increase in temperature
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Answer:
(27.3 ± 0.2)°C
Explanation:
Initial temperature, Q1 = (25.4 ± 0.1)°C
Final temperature, Q2 = (52.7 ± 0.1)°C
So, the increase in temperature
= (52.7 ± 0.1)°C – (25.4 ± 0.1)°C
= (52.7 – 25.4)°C ± (0.1 + 0.1)°C
= (27.3 ± 0.2)°C
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