Question

the initial velcity of a bus is a 11m/s. it undergoes uniform acceleration 2ms-2 calculate it's velocity after 12 second


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Answer 1

Answer:

u=11m/s

a=2m/s²

t=12s

v=?

Applying first equation of motion we get-

v=u+at

v=11+12×2

v=11+24

v=35m/s

Hope it helps!!!

Answer 2

Answer:

final velocity = 35m/s

Explanation:

initial velocity (u) = 11m/s

time (t) = 12s

acceleration (a) = 2m/s^2

final velocity (v) = ?

v = u+at

v = 11+2*12

v = 11+24

v = 35m/s