Question

the initial velocity of a body is 10m/s . if it is moving with a uniform acceleration of 3m/s² on the direction of motion, calculate the distance covered by the body in 20s​

Answer 1

Answer:

Answer:800m

Explanation:

THE INITIAL VELOCITY OF THE BODY, U = 10M/S

ACCELERATION OF THE BODY, A = 3M/S²

TIME,T = 20S

TO FIND DISTANCE, S

S= UT+1/2AT²

S = 10*20+1/2[3*(20)²]

S = 200+1/2[3*400]

S = 200+1/2[1200]

S = 200+600

S = 800

SO, THE DISTANCE, S COVERED BY THE BODY IS 800m

OR 0.8KM

PLEASE MARK ME AS BRAINLIEST

Answer 2

Given :   initial velocity of a body is 10m/s

uniform acceleration of 3m/s²

To Find : the distance covered by the body in 20s​

Solution:

S = ut + (1/2) at²

S = distance covered

u = initial velocity = 10 m/s

a = acceleration = 3 m/s²

t =  time  = 20 sec

distance covered by the body in 20s​  =   10 (20) + (1/2) * 3 * (20)²

= 200  + 600

= 800 m

Learn More:

A particle is dropped from a height of 80m . Find the distance ...

brainly.in/question/11370407

A ball is dropped from a height of 80ft the ball is such that it ...

brainly.in/question/11471174