The initial velocity of a body moving along a straight line is 8u .it has a uniform acceleration of 6ms-2.the distance covered by body in the 6second of its motion is 41metre .the value of u is
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Answer:
Dnth=u+a/2(2n-1)
- 41=8u+6/2(12-1)
- 41=8u+3(11)
- 41-33=8u
- u=8/8
- u=1m per sec
Explanation:
d means distance
u means initial velocity
a means acceleration
n means no. of seconds
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