the initial velocity of a body moving along a straight line is u it has a uniform acceleration of 6 metre per second square the distance covered by the body in the 6th second of its motion is 41 m .the value of U is
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The value of initial velocity, u is 8 m/s.
Given,
Uniform acceleration, a = 6 m/s
distance covered at sixth second, s = 41 m
To Find,
initial velocity, u=?
Solution,
We can solve this problem using the equations of motion.
We have been given the distance covered at the 6th second of the body, s
⇒ s = s6 - s5
According to equations of motions, the distance covered by a body in t seconds with a uniform acceleration u is given by:
s = ut + 1/2 at^2
Therefore, the equation of the distance covered at the sixth second therefore becomes:
⇒ s = u×(6) + 1/2 (6)×(6)^2 - u×(5) - 1/2 (6)×(5)^2
⇒ 41 = 6u + 3×36 - 5u - 1/2 a×25
⇒ 41 = u + 108 - 75
⇒ 41 = u + 33
⇒ u = 41 - 33
⇒ u = 8 m/s
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