Question

The initial velocity of a body moving along a straight lines is 7m//s. It has a uniform acceleration of 4 m//s^(2) the distance covered by the body in the 5^(th) second of its motion is-

Answer 1

Answer:

u= 7 m/s

a= 4 m/s^2

t= 5s

s= ?

s= ut+ 1/2at^2

 =7*5 + 1/2*4*(5)^2

 = 35+ 50

 =85 m

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