the initial velocity of a car is 15m/s it moves with an acceleration of 2m/s2 what will be its speed after 25 sec
Answers
HERE YOUR ANSWER
GIVEN
initial velocity (u) = 15ms^-1
acceleration (a) = 2ms^-2
time = 25s
SOLUTION
we know a kinematic equation
that is V = u+at
where v is final velocity
u = initial velocity
a = acceleration
t= time
v=u +at
= 15 + 2 (25)
= 15+50
THEREFORE V =65ms^-1 (SPEED)
HOPE IT'S CORRECT
THANKYOU
Answer:
Final speed is 65 m/s
Explanation:
As per the question,
initial velocity(u)= 15 m/s
acceleration(a)= 2 m/s^2
time(t)= 25 s
final speed(v)= ?
We have…
v= u + at
i.e. v= 15 + 2*25 = 15 +50 =65 m/s
therefore, final speed is 65 m/s
The equation is a = Δv / Δt = (vf - vi)/(tf - ti). Subtract the initial velocity from the very last velocity, then divide the result by the time c program language period. The very last end result is your average acceleration over that point.
final velocity (v) of an object equals initial pace (u) of that object plus acceleration (a) of the item instances the elapsed time (t) from u to v. Use well-known gravity, a = 9.80665 m/s2, for equations regarding the Earth's gravitational pressure because the acceleration fee of an object.
Calculating distance from acceleration is as clean as the usage of this method: D = v*t + half of*a*t^2. wherein v is the velocity, t is time, and a is the acceleration.
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