Question

the initial velocity of a car is 5 m /s it accelerates uniformly for 50 seconds and then retards uniformly at 2 m/s2 find the distance covered by the car before it comes to rest. for how much times the car is in the motion

Please solve this fully. ​

Answer 1

Answer:

Solution:

u=5m/s

a= 2m/s2

t= 50 sec

We know that, s= ut + 1/2 at2

s= 5 x 50 + 1/2 x 2 x 50 x 50

s= 250 + 1/1 x 1 x 2500 ( I canceled 2 in 1/2 x 2)

s= 250+ 2500

s= 2750m

We know that, v=u+at

v=0 as it comes to rest in the end

u= 5m/s

a= 2m/s 2

t=?

0= 5+2 x t

5= 2t

5/2 = t

t= 2.5 sec

Hope my answer helps!