The initial velocity of a car is 5m/s. It accelerates uniformly at 0.5m/s2 for 50s and then retards uniformly at 2m/s2. Find the distance covered by the car before it comes to rest. For how much time is the car in motion?
Answers
Answered by
1
v=u+at1
=5+25
=30m/s
v2=v+a2t2
0=30-2t2
t2=15sec
t=t1+t2=50+15=65sec
S1=5×50+1/2×0.5×50×50
=250+625=875m
S2=30×15-1/2×2×15×15
=675m
S=S1+S2
=875+675=1550m
=5+25
=30m/s
v2=v+a2t2
0=30-2t2
t2=15sec
t=t1+t2=50+15=65sec
S1=5×50+1/2×0.5×50×50
=250+625=875m
S2=30×15-1/2×2×15×15
=675m
S=S1+S2
=875+675=1550m
Similar questions