the initial velocity of a particle at( t=0) is u and the acceleration of particle at time t is given by f=at ,where a is a constant .what is the relation for velocity of particle after time t.
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Answered by
70
Hey there,
We can formulate that du/dt=a(t)
du/dt=c^3/2 [where ci is a constant]
Integrating the equation we get-
u(t)=u+2c/5*t^5/2
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
We can formulate that du/dt=a(t)
du/dt=c^3/2 [where ci is a constant]
Integrating the equation we get-
u(t)=u+2c/5*t^5/2
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
07161020:
=> v=u+at2/2
not understood
u know differentiation and integration its just that only
plz mark as brainliest
Abe vo 9 class ki students h
thats the right answer
hey i know differentiation but it was some constants you added was disturbing me
know i m ok an you are right man
Answered by
7
Hey there,
We can formulate that du/dt=a(t)
du/dt=c^3/2 [where ci is a constant]
Integrating the equation we get-
u(t)=u+2c/5*t^5/2
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
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