Physics, asked by Anonymous, 1 year ago

the initial velocity of a particle at( t=0) is u and the acceleration of particle at time t is given by f=at ,where a is a constant .what is the relation for velocity of particle after time t.

Answers

Answered by 07161020
70
Hey there,

We can formulate that du/dt=a(t)

du/dt=c^3/2              [where ci is a constant]

Integrating the equation we get-

u(t)=u+2c/5*t^5/2

PLEASE MARK AS BRAINLIEST IF HELPFUL!!!

Regards
07161020

07161020: => v=u+at2/2
Anonymous: not understood
07161020: u know differentiation and integration its just that only
07161020: plz mark as brainliest
Rakshitsaini: Abe vo 9 class ki students h
07161020: thats the right answer
Anonymous: hey i know differentiation but it was some constants you added was disturbing me
Anonymous: know i m ok an you are right man
Answered by Anonymous
7

Hey there,

We can formulate that du/dt=a(t)

du/dt=c^3/2              [where ci is a constant]

Integrating the equation we get-

u(t)=u+2c/5*t^5/2

PLEASE MARK AS BRAINLIEST IF HELPFUL!!!

Regards

07161020

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