Question

the initial velocity of a particle is 10 M per second and its retardation is 2 metre per second square the distance covered in the fifth second of the motion will be

Answer 1

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u = 10 m/s


$a = - 2m \: per \: sec {}^{2}$


t= 5 seconds


S = ?????


Using second equation of motion .....


$s = (10 \times 5) + \frac{1}{2} \times - 2 \times 25$




$s = 50 + ( - 25) \\ \\ s = 25meters$


Hope it helps you


$<marquee > prabhudutt$

Answer 2

u= 10m/s
a=-2m/s^2
t= 5 seconds
s=?

s= ut+1/2at^2
s= 10x5+1/2x-2x5^2
s=50+(-25)
s=25cm