Question

The initial velocity of a particle is 10 m/s and its retardation is 2m/s2. The distance
moved by the particle in 5th sec of its motion is:
a. 1m
b. 1cm
c. 31m
d. 52 m

Pls answer it

Answer 1

Answer:

sorry l don't know..........

Explanation:

.....................

Answer 2

Answer:

1 m

Explanation:

Distance moved in tth second ,s= u + ½ a(2t-1)

Here, u= 10 m/s

         t= 5 s

         a= -2 m/s²

∴Distance moved in 5th second, s₅= 10 + ½×(-2)×(2×5-1)

                                                             = 10+ (-1)×9

                                                             = 10+(-9)

                                                             =10-9

                                                             =1

∴Distance moved in 5th second of the motion of particle is 1 m.