Question

the initial velocity of a particle is 10 m/s and its retardation is 8 X 9/2 = 36. THE distance covered by a particle in the 5th second of its motion

Answer 1

Explanation:

Given,

u=10m/s

a=−2m/s2

n=5

The distance covered by the particle in nth second is

Sn=u+2a(2n−1)

S5=10−22(2×5−1)

S5=10−9=1m

Answer 2

Explanation:

see your answer in the image

1m is answer