Question

The initial velocity of a particle is 10 m/sec and its
retardation is 2 m/sec2. the distance moved by the
particle in 5th sec of its motion is :​

Answer 1

Answer:

25m

Explanation:

u=10m/s

a=-2m/s^2

t=5s

s=ut+1/2at^2

s=50+(-25)=25m