Question

the initial velocity of a particle is 10 metre per second and its retardation is 2 metre per second square the distance moved by the particle in fifth second of its motion is
a)31m
b)52m
c)1m
d)1cm​

Answer 1

Answer:

(c) 1 m

Explanation:

The underlying speed (initial velocity) u = 10 m/sec

First, we will calculate speed till time =4sec (0 to 4)

At t = 4sec

• From the Newtons First eqn.

V = u +at

• As it get impeded then a = - 2m/s^2

V4 = 10 - 8 = 2 m/sec

At t = 5sec

• Again from Newton's First eqn.

V5 = 10 – 2× 5 = 0 m/sec

Normal speed in fifth second

V = (V4 – V5)/2 = 1 m/sec

What's more, as we realize that

Separation = speed × time

= 1m/sec × 1 sec = 1m

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