Question

The initial velocity of a particle is 10m/s. It is moving with an acceleration of 4m/s^2. The distance covered by the particle after 2 sec is:
1. 6m 2.18m 3.22m 4.28m

Answer 1

Answer:

Given,

u=10m/s

a=−2m/s

2

n=5

The distance covered by the particle in n

th

second is

S

n

=u+

2

a

(2n−1)

S

5

=10−

2

2

(2×5−1)

S

5

=10−9=1m