The initial velocity of a train which is stopped
in 20 s by applying brakes (retardation due to
brakes being 1.5 m s-?) is
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Answer:
30 m/s
Explanation:
initial velocity, u = ?
final velocity, v = 0 m/s
Retardation, a = -1.5 m/s
Time, t = 20 s
Acc to Que,
(v-u)/t = a
(0 - u)/20 = -15/10
-u = -3*20/2
-u = -30 m/s
Therefore, initial velocity, u = 30 m/s
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