The initial velocity of an object is 20 m/s having retardation 2 m/s2. the distance moved by object in first three seconds is
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Answer:
Answer should be 51m.
Explanation:
Given;
u= 20 m/s
a = (-2) m/S2
t= 3s.
By using the equation:
S = ut + 1/2 at^2
S = 20*3 + 1/2* (-2)*(9)
S = 60-9
S = 51 m.
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