Math, asked by bhanwarsinghked91667, 8 months ago

the initial velocity of object is4 m/s square . this object is moving with acceleration of2 m/s Square find velocity and distance

Answers

Answered by gouravkuamrverma2
0

Answer:

Apply first kinematic equation of motion.

v=u+at

a=

t

2

−t

1

v−u

=

15−10

68−48

=4ms

−2

Apply second kinematic equation of motion (from initial velocity, u=0)

v

2

−u

2

=2as

⇒68

2

−0=2×4×s

⇒s=578m

Hence, distance travelled in 15sec is578m

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