the initial velocity of object is4 m/s square . this object is moving with acceleration of2 m/s Square find velocity and distance
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Answer:
Apply first kinematic equation of motion.
v=u+at
a=
t
2
−t
1
v−u
=
15−10
68−48
=4ms
−2
Apply second kinematic equation of motion (from initial velocity, u=0)
v
2
−u
2
=2as
⇒68
2
−0=2×4×s
⇒s=578m
Hence, distance travelled in 15sec is578m
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