Question

the initial velocity of particle is 10 m/s and retardation 2 m/s2 its displacement in 5 sec is​

Answer 1

Answer:

apply s = ut + 1/2×at²

u= 10

acc = -2 as acc is = -( retardation)

time = 5

∴ s = 10×5 - 0.5×2×25or(5²)

s = 50 -25

  = 25 meters

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