Question

The initial velocity of projectile motion is 3i+4i them angle of projectile is

Answer 1

Max height when thrown vertically is 200m.

Hence,h=200 and g=9.8 and we need to calculate u.We know that,

h=u22gh=u22g

200=u22×9.8200=u22×9.8

Or u2=3920u2=3920

u=3920−−−−√u=3920

To calculate max horizaontal distance we need to know the formula of range(horizontal distance travelled by a projectile)

R=u2sin2θgR=u2sin2θg

And sin2θsin2θ will be max when θ=45θ=45 so it would be 1.Again rewriting it we get,

R=u2gR=u2g

=3920√29.8=392029.8

=400m

HOPE IT HELP YOU