Physics, asked by jpsavita1837, 1 year ago

The initial velocity of the particle is 10 m/s and its retardation is 2 m/s2. the distance moved by the particle in the second of its motion is

Answers

Answered by vini117
3
question is not complete.
u=10m/s , a= -2 m/s^2, v=0
then distance ,
s= 100/4
=25 m
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