Question

The initial velocity of the particle is 10 m/s and its retardation is 2 ms 2. The distance moved by the particle in 3rd second of its motion is

Answer 1

Given,

u = 10 m/s

a = -2m/s

n = 3

The distance covered by the particle in n th  sec

Sn = u+a/2 (2n-1)

S3 = 10 + -2/2 (2×3-1)

S3 = 10-5

S3 = 5 m

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