Physics, asked by abhinavdamodara41, 11 months ago

the initial velocity of the particle is 10 m/sec and its retardation is 2m/ sec2 . The distance moved by the particle in 5th second of its motion is ?

Answers

Answered by sohanq8

26

Answer: 1m

Explanation:

S = 10 + (-2)(5-1/2) = 10 - 9 = 1m

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