Question

The initial velocity of the projectile is equal to the velocity acquired by a freely falling body through ` a distance 'h'.Then maximum horizontal range of that projectile is `​

Answer 1

Answer:

this is a correct answer

Answer 2

Answer:

H.R=h²sin2θ/g

Explanation:

Given:

u=h

To find:

H.R(Horizontal Range)

Solution:

H.R=u²sin2θ/g

∵u=h,

H.R=h²sin2θ/g