Question

The inneam diameter of a cylindrical wooden bibe even
and its cuter diameter is 28 cm. The length of the bibe.
5 35 cm. Find the mass of the bibe, it cm of
has a mass of 0.6g.
wood​

Answer 1

Answer:

AcAccordingtotheQuesti

{\boxed{\sf\:{Internal\;Radius}}}

InternalRadius

= r cm

Diameter = 24 cm

\tt{\rightarrow radius(r)=\dfrac{24}{2}}→radius(r)=

2

24

r = 12 cm

Now,

{\boxed{\sf\:{External\;Radius}}}

ExternalRadius

\tt{\rightarrow Radius(R)=\dfrac{28}{2}}→Radius(R)=

2

28

R = 14 cm

{\boxed{\sf\:{Length\;of\;Pipe}}}

LengthofPipe

= 35 cm

\textbf{\underline{Volume\;of\;wood\;that\;is\;used\;in\;Pipe}}

VolumeofwoodthatisusedinPipe

= πR²h - πr²h

= π(R² - r²)h

\tt{\rightarrow\dfrac{22}{7}(14^2 - 12^2)\times 35}→

7

22

(14

2

−12

2

)×35

= 22 × 5(14² - 12²)

= 110(14 - 12)(14 + 12)

= 110 × 2 × 26

= 220 × 26 cm³

Now

{\boxed{\sf\:{Mass\;of\;Wooden\;pipe}}}

MassofWoodenpipe

= Volume × Density of wood

= 220 × 26 × 0.6 gm

\tt{\rightarrow 220\times 26\times\dfrac{6}{10}\times\dfrac{1}{1000}kg}→220×26×

10

6

×

1000

1

kg

\tt{\rightarrow\dfrac{3432}{1000}}→

1000

3432

= 3.432 kg

Step-by-step explanation:

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