The inner and outer circumference of a track are 154 m and 266 m. Find the widths of the track
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Step-by-step explanation:
let outer radius be R
and,inner radius be r
Therefore,outer circumference=2πR
and,inner circumference=2πr
Also,Width = R-r
Now,
outer circumference-inner circumference
=2πR-2πr
=2π(R-r)
but,
outer circumference - inner circumference=286m-154m
=132m
Therefore, 2π(R-r)=132
=> 2×22/7×(R-r)=132
=>R-r=(132×7)/(2×22)
=>R-r=21
Therefore ,width of the track is 21m.
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