The inner and outer circumference of the circle backing track R2 64 and 352 respectively find the the width of the racing track
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Answer:
inner circumference = 264
outer circumference = 352
Let the inner radius be r
ATP
2×22/7 r = 264
=> r = 264 ×1/2 ×7/22
=> r = 42
inner radius = 42
Let the outer radius be R
ATP
2×22/7 R = 352
=> R = 352×1/2×7/22
=> R = 56
outer radius = 56
width = R-r = 56-42 = 14
answer :- 14
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